(27-x^2)/4=0

Solution for (27-x^2)/4=0 equation:

(27-x^2)/4=0

We multiply all the terms by the denominator


(27-x^2)=0

We get rid of parentheses

-x^2+27=0

We add all the numbers together, and all the variables

-1x^2+27=0

a = -1; b = 0; c = +27;
Δ = b2-4ac
Δ = 02-4·(-1)·27
Δ = 108
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{108}=\sqrt{36*3}=\sqrt{36}*\sqrt{3}=6\sqrt{3}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{3}}{2*-1}=\frac{0-6\sqrt{3}}{-2}
=-\frac{6\sqrt{3}}{-2}
=-\frac{3\sqrt{3}}{-1}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{3}}{2*-1}=\frac{0+6\sqrt{3}}{-2}
=\frac{6\sqrt{3}}{-2}
=\frac{3\sqrt{3}}{-1}
$